Physics Q101 – AP-EAMCET 2026

Two waves of amplitude '

A

' and frequency '

v

' are superimposed with each other. After superposition, the maximum intensity is

Clue 1 of 3: Wave Superposition

When two waves superimpose, their amplitudes can add up or cancel out depending on their phase difference.

🧠 Full Solution Path

Step 1: Recall the relationship between intensity and amplitude✦ Active

The intensity ( $I$ ) of a wave is directly proportional to the square of its amplitude ( $A$ ). This relationship is expressed as:

I \propto A^{2}

Step 2: Determine the condition for maximum intensity○ Expand

Maximum intensity occurs when two waves undergo constructive interference. In constructive interference, the waves are in phase, and their amplitudes add up directly to form a resultant wave with a larger amplitude.

💡 Teacher's Secret Hint

Remember that destructive interference leads to minimum intensity, where amplitudes subtract.

Step 3: Calculate the maximum resultant amplitude○ Expand

Given two waves, each with an amplitude of $A$ , the maximum resultant amplitude ( $A_{m a x}$ ) due to constructive interference is the sum of their individual amplitudes:

A_{m a x} = A + A = 2 A

Step 4: Calculate the maximum intensity○ Expand

Now, substitute the maximum resultant amplitude ( $A_{m a x} = 2 A$ ) into the intensity-amplitude relationship ( $I \propto A^{2}$ ):

I_{m a x} \propto (A_{m a x})^{2}

I_{m a x} \propto (2 A)^{2}

I_{m a x} \propto 4 A^{2}

Thus, the maximum intensity is proportional to $4 A^{2}$ .

💡 Teacher's Secret Hint

Make sure to square the entire resultant amplitude, including the numerical factor.

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Physics Question 101 – AP-EAMCET 2026

Clue 1 of 3: Wave Superposition

🧠 Full Solution Path