StemCET Logo

Maths Question 21 – JEE-MAIN 2025

If the number of seven-digit numbers, such that the sum of their digits is even, is mn10n; m,n{1,2,3,...,9}, then m+n is equal to _______

The sum of digits is even if there is an even number of odd digits. This can be simplified by considering the parity of the sum of the first k1 digits and the k-th digit.

Step 1: Calculate the number of seven-digit numbers with an even sum of digits✦ Active

A seven-digit number d1d2d3d4d5d6d7 has d1{1,...,9} (9 choices) and di{0,...,9} for i=2,...,7 (10 choices each). Consider the first six digits d1,...,d6. The number of ways to choose these digits is 9×105. Let S6=d1+...+d6. The parity of S6 can be either even or odd.

For the total sum S7=S6+d7 to be even:

- If S6 is even, d7 must be even. There are 5 even digits (0, 2, 4, 6, 8).

- If S6 is odd, d7 must be odd. There are 5 odd digits (1, 3, 5, 7, 9).

In both scenarios, for any combination of the first six digits, there are exactly 5 choices for d7 that make the total sum S7 even. Therefore, the total number of seven-digit numbers with an even sum of digits is 9×105×5=45×105.

Step 2: Match the result with the given form mn10n○ Expand

We are given that the number of such seven-digit numbers is mn10n, where m,n{1,2,3,...,9}. We have calculated this number to be 45×105. Comparing the two forms:

mn10n=45×105

By comparing the powers of 10, we can deduce n=5. Substituting n=5 into the equation:

m5=45

Solving for m, we get m=455=9. Both m=9 and n=5 satisfy the condition m,n{1,2,...,9}.

💡 Teacher's Secret Hint

Ensure that the values of m and n fall within the specified range of {1,2,...,9}.

Step 3: Calculate m+n○ Expand

Now, we need to find the value of m+n:

m+n=9+5=14
✦ STEM Console utilizes AI models to generate step-by-step explanations and math clues. AI can make mistakes.