StemCET Logo

Maths Question 21 – JEE-MAIN 2025

If the number of seven-digit numbers, such that the sum of their digits is even, is m⋅n⋅10n; m,n∈{1,2,3,...,9}, then m+n is equal to _______

The sum of digits is even if there is an even number of odd digits. This can be simplified by considering the parity of the sum of the first k−1 digits and the k-th digit.

Step 1: Calculate the number of seven-digit numbers with an even sum of digits✦ Active

A seven-digit number d1d2d3d4d5d6d7 has d1∈{1,...,9} (9 choices) and di∈{0,...,9} for i=2,...,7 (10 choices each). Consider the first six digits d1,...,d6. The number of ways to choose these digits is 9×105. Let S6=d1+...+d6. The parity of S6 can be either even or odd.

For the total sum S7=S6+d7 to be even:

- If S6 is even, d7 must be even. There are 5 even digits (0, 2, 4, 6, 8).

- If S6 is odd, d7 must be odd. There are 5 odd digits (1, 3, 5, 7, 9).

In both scenarios, for any combination of the first six digits, there are exactly 5 choices for d7 that make the total sum S7 even. Therefore, the total number of seven-digit numbers with an even sum of digits is 9×105×5=45×105.

Step 2: Match the result with the given form m⋅n⋅10n○ Expand

We are given that the number of such seven-digit numbers is m⋅n⋅10n, where m,n∈{1,2,3,...,9}. We have calculated this number to be 45×105. Comparing the two forms:

m⋅n⋅10n=45×105

By comparing the powers of 10, we can deduce n=5. Substituting n=5 into the equation:

m⋅5=45

Solving for m, we get m=455=9. Both m=9 and n=5 satisfy the condition m,n∈{1,2,...,9}.

💡 Teacher's Secret Hint

Ensure that the values of m and n fall within the specified range of {1,2,...,9}.

Step 3: Calculate m+n○ Expand

Now, we need to find the value of m+n:

m+n=9+5=14
✦ STEM Console utilizes AI models to generate step-by-step explanations and math clues. AI can make mistakes.