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Chemistry Question 62 – JEE-MAIN 2025

Identify the diamagnetic octahedral complex ions from below ; A. [Mn(CN)6]3 B. [Co(NH3)6]3+ C. [Fe(CN)6]4 D. [Co(H2O)3F3] Choose the correct answer from the options given below:

Diamagnetic substances are those that have no unpaired electrons, meaning all electrons are paired.

Step 1: Determine Oxidation State and d-electron Configuration✦ Active

For each complex, calculate the oxidation state of the central metal ion and determine its d-electron configuration:

A. [Mn(CN)6]3Mn3+(d4)B. [Co(NH3)6]3+Co3+(d6)C. [Fe(CN)6]4Fe2+(d6)D. [Co(H2O)3F3]Co3+(d6)
Step 2: Analyze Ligand Field Strength and Electron Pairing○ Expand

Identify the ligand field strength (strong field ligand, SFL, or weak field ligand, WFL) and determine the number of unpaired electrons for each octahedral complex:

A. [Mn(CN)6]3CN (SFL).d4 (low spin, t2g4eg0). Unpaired electrons = 2. (Paramagnetic)B. [Co(NH3)6]3+NH3 (SFL).d6 (low spin, t2g6eg0). Unpaired electrons = 0. (Diamagnetic)C. [Fe(CN)6]4CN (SFL).d6 (low spin, t2g6eg0). Unpaired electrons = 0. (Diamagnetic)D. [Co(H2O)3F3]H2O,F (WFL).d6 (high spin, t2g4eg2). Unpaired electrons = 4. (Paramagnetic)
💡 Teacher's Secret Hint

Remember that CN and NH3 are strong field ligands, while H2O and F are weak field ligands.

Step 3: Identify Diamagnetic Complexes○ Expand

Diamagnetic complexes are those with zero unpaired electrons. Based on the analysis, complexes B and C are diamagnetic.

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