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Chemistry Question 57 – JEE-MAIN 2026

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First order gas phase reaction A→B+C pi = initial pressure of gas A, pt = total pressure of the reaction mixture at time t Expression of rate constant (k) is

Understand how the partial pressures of reactants and products change over time based on the reaction stoichiometry.

● Video Walkthrough
Step 1: Set up pressure table for the reaction✦ Active

For the first-order gas phase reaction A→B+C, let pi be the initial pressure of A. At time t, let x be the pressure of A that has reacted.

Reaction:A→B+CInitial pressure:pi00Pressure at time t:pi−xxx
Step 2: Relate total pressure to initial pressure and reacted pressure○ Expand

The total pressure of the reaction mixture at time t, pt, is the sum of the partial pressures of all components:

pt=PA+PB+PC=(pi−x)+x+x=pi+x

From this, we can express x in terms of pi and pt: x=pt−pi. Now, substitute x back into the expression for the partial pressure of A at time t, PA:

PA=pi−x=pi−(pt−pi)=2pi−pt
💡 Teacher's Secret Hint

Ensure correct algebraic manipulation when substituting x.

Step 3: Apply the integrated rate law for a first-order reaction○ Expand

For a first-order gas phase reaction, the rate constant k is given by the integrated rate law:

k=1tln⁡PA(initial)PA(at time t)

Substitute PA(initial)=pi and PA(at time t)=2pi−pt into the equation:

k=1tln⁡pi2pi−pt

This expression matches option 1.

💡 Teacher's Secret Hint

Remember that for gas phase reactions, partial pressures are used instead of concentrations in the rate law.

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