Match the LIST-I with LIST-II LIST-I A. Planck's constant B. Stopping potential C. Work function D. Threshold frequency LIST-II I. ML2T-2 II. T-1 III. ML2T-1 IV. ML2T-3A-1 Choose the correct answer from the options given below:

The correct answer is Option 1. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Physics Q26 – JEE-MAIN 2026

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Home Physics Dual Nature of MatterQuestion #81

Match the LIST-I with LIST-II

\begin{array}{lcl} List-I & List-II \\ A. Planck's constant & I. M L^{2} T^{- 2} \\ B. Stopping potential & II. T^{- 1} \\ C. Work function & III. M L^{2} T^{- 1} \\ D. Threshold frequency & IV. M L^{2} T^{- 3} A^{- 1} \end{array}

Choose the correct answer from the options given below:

Clue 1 of 3: Conceptual Principle

Understanding the fundamental definitions of physical quantities is crucial for determining their dimensions.

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Ninja Strategy•Dimensional Analysis of Planck's Constant

Quickly determine the dimensions of Planck's constant ( $M L^{2} T^{- 1}$ ) and eliminate options that do not match, as it is a unique dimension among the choices provided for List-II.

🧠 Full Solution Path

Step 1: Determine the dimensions of fundamental quantities✦ Active

The fundamental dimensions are Mass ( $M$ ), Length ( $L$ ), Time ( $T$ ), and Electric Current ( $A$ ). We will use these to derive the dimensions of the given quantities.

Step 2: Calculate dimensions for each item in List-I○ Expand

A. Planck's constant ( $h$ ): From $E = h ν$ , $h = E / ν$ . Dimensions of Energy $[E] = [M L^{2} T^{- 2}]$ , Dimensions of Frequency $[ν] = [T^{- 1}]$ . So, $[h] = [M L^{2} T^{- 2}] / [T^{- 1}] = [M L^{2} T^{- 1}]$ . This matches List-II (III).

B. Stopping potential ( $V_{s}$ ): From $K E_{m a x} = e V_{s}$ , $V_{s} = K E_{m a x} / e$ . Dimensions of Energy $[K E_{m a x}] = [M L^{2} T^{- 2}]$ , Dimensions of Charge $[e] = [A T]$ . So, $[V_{s}] = [M L^{2} T^{- 2}] / [A T] = [M L^{2} T^{- 3} A^{- 1}]$ . This matches List-II (IV).

C. Work function ( $ϕ$ ): Work function is a form of energy. So, $[ϕ] = [M L^{2} T^{- 2}]$ . This matches List-II (I).

D. Threshold frequency ( $u_{0}$ ): Threshold frequency is a type of frequency. So, $[u_{0}] = [T^{- 1}]$ . This matches List-II (II).

Step 3: Match the quantities to their dimensions and identify the correct option○ Expand

Based on the calculations: A-III, B-IV, C-I, D-II. Comparing this with the given options, option 1 is the correct match.

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Physics Question 26 – JEE-MAIN 2026

Clue 1 of 3: Conceptual Principle

🧠 Full Solution Path