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Maths Question 11 – JEE-MAIN 2026

If sin(π18)sin(5π18)sin(7π18)=K, then the value of sin(10Kπ3) is:

The angles π18, 5π18, and 7π18 can be expressed in the form θ, 60θ, and 60+θ.

Step 1: Evaluate K using trigonometric identity✦ Active

The given product is sin(π18)sin(5π18)sin(7π18). Let θ=π18=10. Then the angles are 10, 50, 70. These can be written as θ, 60θ, 60+θ. We use the identity sinθsin(60θ)sin(60+θ)=14sin(3θ).

K=sin(10)sin(50)sin(70)=14sin(3×10)=14sin(30) K=14×12=18
Step 2: Substitute K into the expression to be found○ Expand

Now we need to find the value of sin(10Kπ3). Substitute K=18 into the expression.

sin(10Kπ3)=sin(10×18×π3)=sin(10π24)=sin(5π12)
Step 3: Calculate the final sine value○ Expand

Convert 5π12 to degrees and evaluate the sine value. 5π12=5×18012=5×15=75. We can use the sum formula for sine.

sin(75)=sin(45+30)=sin(45)cos(30)+cos(45)sin(30) =12×32+12×12 =322+122=3+122

This matches option 1.

💡 Teacher's Secret Hint

Remember common trigonometric values for angles like 30,45,60 and how to combine them for angles like 75.

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