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Physics Question 28 – JEE-MAIN 2025

An object of mass 1000 g experiences a time dependent force F=(2ti^+3t2j^)N. The power generated by the force at time t is:

Power is the rate at which work is done, and for a force acting on an object, it is given by the dot product of the force and the velocity of the object.

🥷
Ninja StrategyDimensional Analysis of Time Exponents

By analyzing how the time variable t propagates through the equations for acceleration, velocity, and power, one can determine the expected exponents of t in the final power expression, eliminating options with incorrect time dependencies.

Step 1: Calculate Acceleration and Velocity✦ Active

Given mass m=1000 g=1 kg and force F=(2ti^+3t2j^) N. Using Newton's second law, a=Fm.

a=(2ti^+3t2j^)1=(2ti^+3t2j^) m/s2

Assuming the object starts from rest (initial velocity is zero), integrate acceleration to find velocity v=adt.

v=(2ti^+3t2j^)dt=(t2i^+t3j^) m/s
Step 2: Calculate Power○ Expand

The instantaneous power generated by the force is given by the dot product of the force vector and the velocity vector, P=Fv.

P=(2ti^+3t2j^)(t2i^+t3j^)

Perform the dot product:

P=(2t)(t2)+(3t2)(t3)=2t3+3t5
Step 3: Final Answer○ Expand

The power generated by the force at time t is (2t3+3t5) W. Comparing this with the given options, option 2 matches the result.

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