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Maths Question 8 – JEE-MAIN 2026

The mean deviation about the mean for the data xi579101215fi862226 is equal to:

Mean deviation about the mean measures the average absolute difference between each data point and the mean of the data.

Step 1: Calculate the Mean (x¯)✦ Active

First, calculate the sum of frequencies (N) and the sum of the product of frequency and data points (fixi). fi=8+6+2+2+2+6=26 fixi=(5×8)+(7×6)+(9×2)+(10×2)+(12×2)+(15×6) =40+42+18+20+24+90=234 Now, calculate the mean:

x¯=fixifi=23426=9
Step 2: Calculate Absolute Deviations and their Weighted Sum○ Expand

Next, calculate the absolute deviation of each data point from the mean, |xix¯|, and then multiply by its corresponding frequency fi. Sum these products to get fi|xix¯|. For xi=5, |59|=4, fi|xix¯|=8×4=32 For xi=7, |79|=2, fi|xix¯|=6×2=12 For xi=9, |99|=0, fi|xix¯|=2×0=0 For xi=10, |109|=1, fi|xix¯|=2×1=2 For xi=12, |129|=3, fi|xix¯|=2×3=6 For xi=15, |159|=6, fi|xix¯|=6×6=36

fi|xix¯|=32+12+0+2+6+36=88
💡 Teacher's Secret Hint

Ensure all absolute deviations are positive before multiplying by frequency.

Step 3: Calculate the Mean Deviation about the Mean○ Expand

Finally, divide the sum of fi|xix¯| by the total frequency fi to find the mean deviation about the mean.

MD=fi|xix¯|fi=8826=4413

Comparing this result with the given options, we find that it matches option 3.

💡 Teacher's Secret Hint

Always simplify fractions to their lowest terms if possible.

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