Chemistry Q61 – JEE-MAIN 2025

Home Chemistry Basic Organic ChemistryQuestion #171

Match the LIST-I with LIST-II

\begin{array}{lcl} LIST-I & LIST-II \\ (Reagent) & (Functional Group detected) \\ A. Sodium bicarbonate solution & I. double bond/ unsaturation \\ B. Neutral ferric chloride & II. carboxylic acid \\ C. ceric ammonium nitrate & III. phenolic -OH \\ {D. alkaline KMnO}_{4} & IV. alcoholic -OH \end{array}

Choose the correct answer from the options given below:

Clue 1 of 3: Functional Group Tests

Recall the characteristic reagents used for the detection of different organic functional groups.

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Ninja Strategy•Identify Key Tests First

Recognize the most common and distinct tests (e.g., sodium bicarbonate for carboxylic acids, alkaline $K M n O_{4}$ for unsaturation) to quickly eliminate options and narrow down the choices.

🧠 Full Solution Path

Step 1: Identify Reagent-Functional Group Pairs✦ Active

Match each reagent in List-I with the functional group it is used to detect in List-II based on standard qualitative organic analysis tests:

\begin{array}{ll} A. Sodium bicarbonate solution & \to II. carboxylic acid (reacts to produce C O_{2}) \\ B. Neutral ferric chloride & \to III. phenolic -OH (forms colored complex with F e^{3 +}) \\ C. Ceric ammonium nitrate & \to IV. alcoholic -OH (gives red color) \\ {D. Alkaline KMnO}_{4} & \to I. double bond/ unsaturation (decolorizes K M n O_{4}) \end{array}

Step 2: Formulate the Correct Combination○ Expand

Based on the matches from Step 1, the correct combination is A-II, B-III, C-IV, D-I.

Step 3: Select the Matching Option○ Expand

Compare this combination with the given options. Option 1 matches the derived combination.

💡 Teacher's Secret Hint

Ensure careful cross-referencing of all four pairs to avoid errors.

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Chemistry Question 61 – JEE-MAIN 2025

Clue 1 of 3: Functional Group Tests

🧠 Full Solution Path