Match List I with List II. List I (Molecule) A. ethane B. ethene C. carbon molecule, C2 D. ethyne List II (Number and types of bond/s between two carbon atoms) I. one sigma-bond and two pi-bonds II. two pi-bonds III. one sigma-bond IV. one sigma-bond and one pi-bond Choose the correct answer from the options given below:

The correct answer is Option 2. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Chemistry Q67 – NEET-UG 2024

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Home Chemistry Chemical BondingQuestion #235

Match List I with List II.

\begin{array}{lcl} List I (Molecule) & List II (Number and types of bond/s between two carbon atoms) \\ A. ethane & I. one σ -bond and two π -bonds \\ B. ethene & II. two π -bonds \\ C. carbon molecule, C_{2} & III. one σ -bond \\ D. ethyne & IV. one σ -bond and one π -bond \end{array}

Choose the correct answer from the options given below:

Clue 1 of 3: Understand the basic types of covalent bonds

Covalent bonds can be single, double, or triple, each composed of a specific combination of sigma ( $σ$ ) and pi ( $π$ ) bonds.

🧠 Full Solution Path

Step 1: Analyze Bonding in Each Molecule✦ Active

Let's determine the number of $σ$ and $π$ bonds between the two carbon atoms for each molecule in List I:

A. Ethane ( $C_{2} H_{6}$ ): Has a C-C single bond. A single bond consists of one $σ$ -bond. (Matches List II - III)

B. Ethene ( $C_{2} H_{4}$ ): Has a C=C double bond. A double bond consists of one $σ$ -bond and one $π$ -bond. (Matches List II - IV)

C. Carbon molecule ( $C_{2}$ ): According to molecular orbital theory, the $C_{2}$ molecule has a bond order of 2, consisting of two $π$ -bonds and no $σ$ -bond in its ground state. (Matches List II - II)

D. Ethyne ( $C_{2} H_{2}$ ): Has a C $\equiv$ C triple bond. A triple bond consists of one $σ$ -bond and two $π$ -bonds. (Matches List II - I)

💡 Teacher's Secret Hint

Remember the general rule: single bond = $1 σ$ , double bond = $1 σ + 1 π$ , triple bond = $1 σ + 2 π$ . The $C_{2}$ molecule is an exception to this simple rule for diatomic molecules.

Step 2: Match List I with List II○ Expand

Based on the analysis:

A. Ethane $\to$ III (one $σ$ -bond)

B. Ethene $\to$ IV (one $σ$ -bond and one $π$ -bond)

C. Carbon molecule, $C_{2} \to$ II (two $π$ -bonds)

D. Ethyne $\to$ I (one $σ$ -bond and two $π$ -bonds)

Step 3: Select the Correct Option○ Expand

The correct matching sequence is A-III, B-IV, C-II, D-I. Comparing this with the given options, option (2) matches this sequence.

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Chemistry Question 67 – NEET-UG 2024

Clue 1 of 3: Understand the basic types of covalent bonds

🧠 Full Solution Path