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Physics Question 99 – AP-EAMCET 2026

Two moles of ideal gas undergo isothermal expansion from volume V to 2V at temperature T. The work done during the expansion is

An isothermal process is a thermodynamic process that occurs at a constant temperature. For an ideal gas undergoing such a process, the change in internal energy is zero.

Step 1: Identify the Process and Given Parameters✦ Active

The problem describes an isothermal expansion of an ideal gas. We are given the following parameters:

Number of moles (n) = 2

Initial volume (Vinitial) = V

Final volume (Vfinal) = 2V

Temperature = T (constant)

Gas constant = R

💡 Teacher's Secret Hint

Always start by listing all the knowns and identifying the type of thermodynamic process involved, as this dictates the formula to use.

Step 2: Recall the Formula for Work Done in Isothermal Expansion○ Expand

For a reversible isothermal expansion of an ideal gas, the work done by the gas is given by the formula:

W=nRTln(VfinalVinitial)
💡 Teacher's Secret Hint

Remember that work done BY the system is positive in this convention, while work done ON the system would have a negative sign.

Step 3: Substitute the Given Values into the Formula○ Expand

Substitute the identified values into the work formula:

W=(2)RTln(2VV)
💡 Teacher's Secret Hint

Be careful with the number of moles (n) and ensure it's correctly substituted. In some problems, n might be implicitly 1 if not specified.

Step 4: Simplify the Expression to Find the Work Done○ Expand

Simplify the expression by canceling V from the ratio:

W=2RTln(2)

This result corresponds to option 2.

💡 Teacher's Secret Hint

Ensure you correctly evaluate the natural logarithm of the volume ratio. ln(2) is a common value in such problems.

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