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Maths Question 2 – JEE-MAIN 2026

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Let the circles C1:|z|=r and C2:|z−3−4i|=5, z∈C, be such that C2 lies within C1. If z1 moves on C1, z2 moves on C2 and min|z1−z2|=2, then max|z1−z2| is equal to :

Understand the properties of circles in the complex plane, specifically their centers and radii, and how distances between points on them are related to the distance between their centers.

● Video Walkthrough
Step 1: Identify Circle Parameters and Distance between Centers✦ Active

Circle C1:|z|=r. Its center is O1=0 and its radius is R1=r.

Circle C2:|z−(3+4i)|=5. Its center is O2=3+4i and its radius is R2=5.

The distance between the centers O1 and O2 is d=|O1−O2|=|0−(3+4i)|=|−3−4i|.

d=(−3)2+(−4)2=9+16=25=5.
Step 2: Use Minimum Distance to Find Radius r○ Expand

Since C2 lies within C1, the minimum distance between a point on C1 and a point on C2 is given by R1−d−R2.

We are given that min|z1−z2|=2. Therefore, we can set up the equation:

r−d−R2=2

Substitute the known values d=5 and R2=5:

r−5−5=2

Solving for r:

r−10=2⟹r=12.

This value of r=12 satisfies the condition for C2 to be within C1, which is d+R2<R1⟹5+5<12⟹10<12.

💡 Teacher's Secret Hint

Ensure the condition for one circle lying within another (d+R2<R1) is met after calculating r.

Step 3: Calculate Maximum Distance○ Expand

The maximum distance between a point on C1 and a point on C2 is given by R1+d+R2.

Substitute the values r=12, d=5, and R2=5:

max|z1−z2|=r+d+R2=12+5+5=22.
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