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Maths Question 2 – JEE-MAIN 2026

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Let the circles C1:|z|=r and C2:|z34i|=5, zC, be such that C2 lies within C1. If z1 moves on C1, z2 moves on C2 and min|z1z2|=2, then max|z1z2| is equal to :

Understand the properties of circles in the complex plane, specifically their centers and radii, and how distances between points on them are related to the distance between their centers.

Video Walkthrough
Step 1: Identify Circle Parameters and Distance between Centers✦ Active

Circle C1:|z|=r. Its center is O1=0 and its radius is R1=r.

Circle C2:|z(3+4i)|=5. Its center is O2=3+4i and its radius is R2=5.

The distance between the centers O1 and O2 is d=|O1O2|=|0(3+4i)|=|34i|.

d=(3)2+(4)2=9+16=25=5.
Step 2: Use Minimum Distance to Find Radius r○ Expand

Since C2 lies within C1, the minimum distance between a point on C1 and a point on C2 is given by R1dR2.

We are given that min|z1z2|=2. Therefore, we can set up the equation:

rdR2=2

Substitute the known values d=5 and R2=5:

r55=2

Solving for r:

r10=2r=12.

This value of r=12 satisfies the condition for C2 to be within C1, which is d+R2<R15+5<1210<12.

💡 Teacher's Secret Hint

Ensure the condition for one circle lying within another (d+R2<R1) is met after calculating r.

Step 3: Calculate Maximum Distance○ Expand

The maximum distance between a point on C1 and a point on C2 is given by R1+d+R2.

Substitute the values r=12, d=5, and R2=5:

max|z1z2|=r+d+R2=12+5+5=22.
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