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Chemistry Question 140 – AP-EAMCET 2026

A compound is formed by elements A and B. Element B forms ccp structure. Atoms of A occupy x% of tetrahedral voids. All the octahedral voids are vacant. Compound formula is A2B3. What is x%?

Understand the relationship between the number of atoms in a close-packed structure and the number of tetrahedral and octahedral voids.

Step 1: Determine the number of atoms and voids in the ccp structure✦ Active

In a cubic close-packed (ccp) structure, the number of atoms per unit cell is 4. Let element B form the ccp lattice, so the number of B atoms per unit cell, NB, is 4.

For a ccp structure, the number of tetrahedral voids is twice the number of atoms, and the number of octahedral voids is equal to the number of atoms.

Number of B atoms (NB)=4
Number of tetrahedral voids=2×NB=2×4=8
Number of octahedral voids=NB=4
💡 Teacher's Secret Hint

Remember that ccp is equivalent to FCC (Face-Centered Cubic) structure, where the number of atoms per unit cell is 4.

Step 2: Calculate the number of A atoms based on void occupancy○ Expand

It is given that all octahedral voids are vacant. Atoms of A occupy x% of the tetrahedral voids.

So, the number of A atoms, NA, can be expressed as:

NA=x100×(Number of tetrahedral voids)
NA=x100×8
💡 Teacher's Secret Hint

Ensure you use the correct type of void (tetrahedral) for element A's occupancy, as specified in the problem.

Step 3: Use the compound formula to find the value of x○ Expand

The compound formula is given as A2B3. This means the ratio of A atoms to B atoms in the compound is 2:3.

NANB=23

Substitute the expressions for NA and NB from the previous steps:

x100×84=23

Now, simplify and solve for x:

8x400=23
2x100=23
x50=23
x=2×503
x=1003
x33.33

Therefore, x% is approximately 33.3%.

💡 Teacher's Secret Hint

Be careful with algebraic manipulation. Double-check your simplification steps to avoid errors.

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