Chemistry Question 140 – AP-EAMCET 2026
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In a cubic close-packed (ccp) structure, the number of atoms per unit cell is 4. Let element B form the ccp lattice, so the number of B atoms per unit cell,
For a ccp structure, the number of tetrahedral voids is twice the number of atoms, and the number of octahedral voids is equal to the number of atoms.
Remember that ccp is equivalent to FCC (Face-Centered Cubic) structure, where the number of atoms per unit cell is 4.
It is given that all octahedral voids are vacant. Atoms of A occupy
So, the number of A atoms,
Ensure you use the correct type of void (tetrahedral) for element A's occupancy, as specified in the problem.
The compound formula is given as
Substitute the expressions for
Now, simplify and solve for
Therefore,
Be careful with algebraic manipulation. Double-check your simplification steps to avoid errors.
