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Chemistry Question 61 – JEE-MAIN 2026

Which of the following sets includes all the species that will change the orange colour of K2Cr2O7 in acidic medium ?

Potassium dichromate (K2Cr2O7) in acidic medium acts as a strong oxidizing agent, meaning it will get reduced.

Step 1: Understand the role of Dichromate in Acidic Medium✦ Active

In acidic medium, the dichromate ion (Cr2O72), which is orange, acts as a strong oxidizing agent. It gets reduced to the green chromium(III) ion (Cr3+). The half-reaction is:

Cr2O72(orange)+14H++6e2Cr3+(green)+7H2O

Therefore, any species that can be oxidized by Cr2O72 (i.e., acts as a reducing agent) will cause this color change.

Step 2: Evaluate each option for reducing agents○ Expand

We need to identify the set where all species can be oxidized (are reducing agents):

1. Fe2+ can be oxidized to Fe3+. Sn2+ can be oxidized to Sn4+. I can be oxidized to I2. S2 can be oxidized to S or SO2 or SO42. All are reducing agents.

2. Fe3+ is already in a higher oxidation state and cannot be oxidized further by Cr2O72. It is not a reducing agent in this context.

3. Sn4+ is already in its highest oxidation state and cannot be oxidized further by Cr2O72. It is not a reducing agent.

4. Fe3+, SO42 (sulfur in +6 oxidation state), and Sn4+ cannot be oxidized further by Cr2O72. They are not reducing agents.

💡 Teacher's Secret Hint

Remember to check the maximum possible oxidation state for each element to determine if it can act as a reducing agent.

Step 3: Conclusion○ Expand

Only the set in option 1 contains all species (Fe2+, Sn2+, I, S2) that are reducing agents and will react with K2Cr2O7 in acidic medium, causing the orange color to change to green.

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