Physics Q27 – JEE-MAIN 2025

Match List - I with List - II

\begin{array}{lcl} List - I & List - II \\ (A) Mass density & (I) [M L^{2} T^{- 3}] \\ (B) Impulse & (II) [M L T^{- 1}] \\ (C) Power & (III) [M L^{2} T^{0}] \\ (D) Moment of inertia & (IV) [M L^{- 3} T^{0}] \end{array}

Choose the correct answer from the options given below :

Understand the fundamental definition of each physical quantity listed in List-I.

Step 1: Determine Dimensions for List-I Quantities✦ Active

Derive the dimensional formula for each quantity in List-I:

\begin{array}{ll} (A) Mass density = \frac{Mass}{Volume} = \frac{M}{L^{3}} = [M L^{- 3} T^{0}] \\ (B) Impulse = Force \times Time = [M L T^{- 2}] \times [T] = [M L T^{- 1}] \\ (C) Power = \frac{Work}{Time} = \frac{Force \times Distance}{Time} = \frac{[M L T^{- 2}] \times [L]}{[T]} = [M L^{2} T^{- 3}] \\ (D) Moment of inertia = Mass \times (Distance)^{2} = [M] \times [L^{2}] = [M L^{2} T^{0}] \end{array}

Step 2: Match with List-II Dimensions○ Expand

Now, match the derived dimensions with the options in List-II:

\begin{array}{ll} (A) [M L^{- 3} T^{0}] & \to (IV) (B) [M L T^{- 1}] & \to (II) (C) [M L^{2} T^{- 3}] & \to (I) (D) [M L^{2} T^{0}] & \to (III) \end{array}

💡 Teacher's Secret Hint

Ensure careful calculation of exponents, especially for time and length.

Step 3: Select the Correct Option○ Expand

Based on the matching, the correct combination is (A)-(IV), (B)-(II), (C)-(I), (D)-(III). This corresponds to option 4.

💡 Teacher's Secret Hint

Double-check each match before finalizing the answer.

✦ STEM Console utilizes AI models to generate step-by-step explanations and math clues. AI can make mistakes.

Physics Question 27 – JEE-MAIN 2025