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Chemistry Question 60 – JEE-MAIN 2025

The d-orbital electronic configuration of the complex among [Co(en)3]3+, [CoF6]3, [Mn(H2O)6]2+ and [Zn(H2O)6]2+ that has the highest CFSE is :

Determine the oxidation state of the central metal ion and its d-electron count for each complex.

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Ninja StrategyStrong Field Ligand Dominance

The highest CFSE is typically found in complexes with strong field ligands that promote low spin configurations, leading to a larger stabilization energy.

Step 1: Determine Oxidation State, d-electron Count, and Spin State for each complex✦ Active

For each complex, identify the oxidation state of the central metal ion, its d-electron configuration, and determine if it's high spin or low spin based on the ligand field strength.

[Co(en)3]3+:Co3+(d6).en is a strong field ligandlow spin.Configuration: t2g6eg0. [CoF6]3:Co3+(d6).F is a weak field ligandhigh spin.Configuration: t2g4eg2. [Mn(H2O)6]2+:Mn2+(d5).H2O is a weak field ligandhigh spin.Configuration: t2g3eg2. [Zn(H2O)6]2+:Zn2+(d10).Configuration: t2g6eg4.
Step 2: Calculate CFSE for each complex○ Expand

Calculate the CFSE for each complex. The highest CFSE corresponds to the most negative value (largest magnitude).

[Co(en)3]3+:CFSE=(0.4×6+0.6×0)Δo+3P=2.4Δo+3P. [CoF6]3:CFSE=(0.4×4+0.6×2)Δo=(1.6+1.2)Δo=0.4Δo. [Mn(H2O)6]2+:CFSE=(0.4×3+0.6×2)Δo=(1.2+1.2)Δo=0. [Zn(H2O)6]2+:CFSE=(0.4×6+0.6×4)Δo=(2.4+2.4)Δo=0.
💡 Teacher's Secret Hint

Remember to include pairing energy (P) for low spin complexes when calculating total CFSE, but for comparing magnitude, focus on the Δo term.

Step 3: Identify the complex with the highest CFSE and its configuration○ Expand

Comparing the CFSE values, [Co(en)3]3+ has the largest negative CFSE (magnitude 2.4Δo), indicating the highest stabilization. Its d-orbital electronic configuration is t2g6eg0.

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