StemCET Logo

Physics Question 33 – JEE-MAIN 2026

A slit of width a is illuminated by light of wavelength λ. The linear separation between 1st and 3rd minima in the diffraction pattern produced on a screen placed at a distance D from the slit system is _______.

Recall the condition for destructive interference (minima) in a single-slit diffraction pattern.

Step 1: Identify the condition for minima in single-slit diffraction✦ Active

For a single slit of width a, the condition for the m-th minimum (destructive interference) is given by:

asinθm=mλ

where θm is the angular position of the m-th minimum, λ is the wavelength of light, and m=±1,±2, (excluding m=0 for minima).

Step 2: Determine the linear position of the minima on the screen○ Expand

For small angles, which is typical for diffraction patterns observed on a screen far from the slit, we can use the approximation sinθmtanθm=ymD, where ym is the linear distance from the central maximum to the m-th minimum on the screen, and D is the distance from the slit to the screen.

Substituting this into the condition from Step 1:

aymD=mλ

Solving for ym, we get the linear position of the m-th minimum:

ym=mλDa
💡 Teacher's Secret Hint

Remember that the small angle approximation is crucial here. If angles are not small, the problem becomes more complex.

Step 3: Calculate the linear separation between the 1st and 3rd minima○ Expand

For the 1st minimum (m=1):

y1=1λDa=λDa

For the 3rd minimum (m=3):

y3=3λDa=3λDa

The linear separation between the 1st and 3rd minima is the absolute difference of their positions:

Δy=|y3y1|=|3λDaλDa|=|(31)λDa|=2λDa
💡 Teacher's Secret Hint

Ensure you correctly identify the 'm' values for the specified minima. The central maximum is at m=0, and minima are indexed starting from m=1 outwards.

✦ STEM Console utilizes AI models to generate step-by-step explanations and math clues. AI can make mistakes.