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Physics Question 27 – NEET-UG 2025

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An unpolarized light beam travelling in air is incident on a medium of refractive index 1.73 at Brewster's angle. Then-

When unpolarized light is incident at Brewster's angle, the reflected light is completely plane-polarized.

● Video Walkthrough
Step 1: Apply Brewster's Law and calculate Brewster's angle✦ Active

Brewster's law states that when unpolarized light is incident at Brewster's angle (ip), the reflected light is completely plane-polarized. The angle is given by tan⁡ip=n, where n is the refractive index of the medium relative to air (n1=1 for air, n2=1.73 for the medium).

tan⁡ip=1.73

Calculating the angle: ip=arctan⁡(1.73). Since tan⁡(60∘)≈1.732, we have ip≈60∘.

Step 2: Determine the nature of reflected and transmitted light and angles○ Expand

At Brewster's angle, the reflected light is completely plane-polarized. According to the law of reflection, the angle of reflection (r) is equal to the angle of incidence (ip). Therefore, r≈60∘.

The transmitted light at Brewster's angle is partially polarized.

Also, at Brewster's angle, the reflected and refracted rays are perpendicular, which means ip+r′=90∘, where r′ is the angle of refraction.

60∘+r′=90∘⟹r′=30∘
💡 Teacher's Secret Hint

Remember that only the reflected light is completely polarized at Brewster's angle; the transmitted light is partially polarized.

Step 3: Evaluate the options○ Expand

Based on our findings:

Option (1) states that reflected light is completely polarized and the angle of reflection is close to 60∘. This is consistent with our calculations.

Option (2) is incorrect because reflected light is completely polarized, not partially, and the angle of reflection is 60∘, not 30∘.

Option (3) is incorrect because transmitted light is partially polarized, not perfectly polarized.

Option (4) is incorrect because transmitted light is partially polarized, not completely polarized.

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