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Physics Question 27 – NEET-UG 2025

An unpolarized light beam travelling in air is incident on a medium of refractive index 1.73 at Brewster's angle. Then-

When unpolarized light is incident at Brewster's angle, the reflected light is completely plane-polarized.

Step 1: Apply Brewster's Law and calculate Brewster's angle✦ Active

Brewster's law states that when unpolarized light is incident at Brewster's angle (ip), the reflected light is completely plane-polarized. The angle is given by tanip=n, where n is the refractive index of the medium relative to air (n1=1 for air, n2=1.73 for the medium).

tanip=1.73

Calculating the angle: ip=arctan(1.73). Since tan(60)1.732, we have ip60.

Step 2: Determine the nature of reflected and transmitted light and angles○ Expand

At Brewster's angle, the reflected light is completely plane-polarized. According to the law of reflection, the angle of reflection (r) is equal to the angle of incidence (ip). Therefore, r60.

The transmitted light at Brewster's angle is partially polarized.

Also, at Brewster's angle, the reflected and refracted rays are perpendicular, which means ip+r=90, where r is the angle of refraction.

60+r=90r=30
💡 Teacher's Secret Hint

Remember that only the reflected light is completely polarized at Brewster's angle; the transmitted light is partially polarized.

Step 3: Evaluate the options○ Expand

Based on our findings:

Option (1) states that reflected light is completely polarized and the angle of reflection is close to 60. This is consistent with our calculations.

Option (2) is incorrect because reflected light is completely polarized, not partially, and the angle of reflection is 60, not 30.

Option (3) is incorrect because transmitted light is partially polarized, not perfectly polarized.

Option (4) is incorrect because transmitted light is partially polarized, not completely polarized.

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