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Chemistry Question 68 – JEE-MAIN 2026

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Which statements are True ? A. In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of Br2 are consumed per mole of an amide B. Hoffmann bromamide reaction is not given by alkyl amides. C. Primary amines can be synthesized by Hoffmann bromamide degradation. D. Secondary amide on reaction with Br2 and NaOH will give secondary amine. E. The by-products of Hoffmann degradation are Na2CO3, NaBr and H2O. Choose the correct answer from the options given below :

Recall the balanced chemical equation for the Hoffmann bromamide degradation to determine the molar ratios of reactants and products.

Step 1: Recall Hoffmann Bromamide Degradation Reaction✦ Active

The general balanced equation for Hoffmann bromamide degradation is:

RCONH2+Br2+4NaOH→RNH2+Na2CO3+2NaBr+2H2O
Step 2: Evaluate Each Statement○ Expand

A. From the equation, 4 moles of NaOH and 1 mole of Br2 are consumed per mole of amide. So, statement A is False (2 moles of Br2 is incorrect). B. Hoffmann bromamide degradation is given by primary amides, which include alkyl amides. So, statement B is False. C. The reaction converts a primary amide (RCONH2) to a primary amine (RNH2). So, statement C is True. D. Hoffmann bromamide degradation is specific to primary amides. Secondary amides (RCONHR′) do not undergo this reaction to form amines. So, statement D is False. E. The by-products shown in the balanced equation are Na2CO3, NaBr, and H2O. So, statement E is True.

💡 Teacher's Secret Hint

Pay close attention to the stoichiometry and the type of amide that reacts.

Step 3: Identify Correct Combination○ Expand

Based on the evaluation, statements C and E are true. Therefore, the correct option is 'C and E only'.

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