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Physics Question 26 – JEE-MAIN 2026

Dimensions of universal gravitational constant (G) in terms of Planck's constant (h), distance (L), mass (M) and time (T) are _______.

Recall the fundamental dimensions of universal gravitational constant (G) and Planck's constant (h) in terms of mass (M), length (L), and time (T).

Step 1: Determine the dimensions of G and h✦ Active

The universal gravitational constant G is derived from Newton's Law of Gravitation, F=Gm1m2r2. Rearranging for G, we get G=Fr2m1m2. The dimensions of force F are [MLT2], distance r are [L], and mass m are [M]. Therefore, the dimensions of G are:

[G]=[MLT2][L]2[M]2=[M1L3T2]

Planck's constant h is derived from the energy of a photon, E=hν, where ν is frequency. Rearranging for h, we get h=Eν. The dimensions of energy E are [ML2T2] and frequency ν are [T1]. Therefore, the dimensions of h are:

[h]=[ML2T2][T1]=[ML2T1]
Step 2: Evaluate the dimensions of each option○ Expand

We need to find an option that, when simplified, yields the dimensions of G, which are [M1L3T2]. Let's check Option 2: [hT1LM2]. Substitute the dimensions of h into this expression:

[hT1LM2]=[ML2T1][T1][L][M2]

Combine the powers of M, L, and T:

Power of M: 12=1Power of L: 2+1=3Power of T: 11=2

So, Option 2 simplifies to [M1L3T2].

💡 Teacher's Secret Hint

Carefully combine the exponents for each fundamental dimension (M, L, T) when multiplying dimensional formulas.

Step 3: Compare with the dimensions of G○ Expand

The calculated dimensions for Option 2, [M1L3T2], exactly match the dimensions of the universal gravitational constant G derived in Step 1. Therefore, Option 2 is the correct answer.

💡 Teacher's Secret Hint

If the first option doesn't match, continue checking the remaining options systematically.

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