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Physics Question 26 – JEE-MAIN 2026

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Dimensions of universal gravitational constant (G) in terms of Planck's constant (h), distance (L), mass (M) and time (T) are _______.

Recall the fundamental dimensions of universal gravitational constant (G) and Planck's constant (h) in terms of mass (M), length (L), and time (T).

● Video Walkthrough
Step 1: Determine the dimensions of G and h✦ Active

The universal gravitational constant G is derived from Newton's Law of Gravitation, F=Gm1m2r2. Rearranging for G, we get G=Fr2m1m2. The dimensions of force F are [MLT−2], distance r are [L], and mass m are [M]. Therefore, the dimensions of G are:

[G]=[MLT−2][L]2[M]2=[M−1L3T−2]

Planck's constant h is derived from the energy of a photon, E=hν, where ν is frequency. Rearranging for h, we get h=Eν. The dimensions of energy E are [ML2T−2] and frequency ν are [T−1]. Therefore, the dimensions of h are:

[h]=[ML2T−2][T−1]=[ML2T−1]
Step 2: Evaluate the dimensions of each option○ Expand

We need to find an option that, when simplified, yields the dimensions of G, which are [M−1L3T−2]. Let's check Option 2: [hT−1LM−2]. Substitute the dimensions of h into this expression:

[hT−1LM−2]=[ML2T−1][T−1][L][M−2]

Combine the powers of M, L, and T:

Power of M: 1−2=−1Power of L: 2+1=3Power of T: −1−1=−2

So, Option 2 simplifies to [M−1L3T−2].

💡 Teacher's Secret Hint

Carefully combine the exponents for each fundamental dimension (M, L, T) when multiplying dimensional formulas.

Step 3: Compare with the dimensions of G○ Expand

The calculated dimensions for Option 2, [M−1L3T−2], exactly match the dimensions of the universal gravitational constant G derived in Step 1. Therefore, Option 2 is the correct answer.

💡 Teacher's Secret Hint

If the first option doesn't match, continue checking the remaining options systematically.

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