Maths Question #21 – JEE-MAIN 2025

Question

Correct Marks : 4 Wrong Marks : 1 Let (1 + x + x^2)^10 = a0 + a1x + a2x^2 + ... + a20x^20. If (a1 + a3 + a5 + ... + a19) - 11a2 = 121k, then k is equal to _______.

Accepted Answer

The correct answer is Option 239. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Maths Question 21 – JEE-MAIN 2025

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