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Physics Question 96 – AP-EAMCET 2026

How much should the temperature of a metal ring of diameter 100 cm to be raised in order to fit it on a wooden disc of diameter 100.6 cm [coefficient of linear expansion of metal = 12×106 \degree C1]

When a material is heated, its dimensions (length, area, volume) generally increase. This phenomenon is called thermal expansion. For a linear dimension like diameter, it expands proportionally to the initial length, the temperature change, and the material's coefficient of linear expansion.

Step 1: Identify Given Parameters and Goal✦ Active

Identify the initial diameter of the metal ring (D0), the final desired diameter (Df), and the coefficient of linear expansion (α). The goal is to find the change in temperature (ΔT) required for the ring to expand to the desired size.

D0=100 cm Df=100.6 cm α=12×106 \degree C1 Find ΔT
💡 Teacher's Secret Hint

Remember that ΔT represents the *change* in temperature, not the final temperature. If an initial temperature were given, we would add ΔT to it to find the final temperature.

Step 2: Calculate the Required Change in Diameter○ Expand

Determine how much the diameter of the ring needs to increase by subtracting the initial diameter from the final desired diameter.

ΔD=DfD0 ΔD=100.6 cm100 cm ΔD=0.6 cm
Step 3: Apply the Linear Thermal Expansion Formula○ Expand

Use the formula for linear thermal expansion, which relates the change in length (or diameter) to the initial length, the coefficient of linear expansion, and the change in temperature.

ΔD=D0αΔT
💡 Teacher's Secret Hint

In this formula, the units of D0 and ΔD must be consistent (e.g., both in cm or both in meters), and the unit of α must be consistent with the unit of temperature change (e.g., \degree C1 for ΔT in \degree C). Also, note that the linear expansion applies to the diameter as well as the circumference of the ring.

Step 4: Solve for the Change in Temperature (ΔT)○ Expand

Rearrange the formula from the previous step to solve for ΔT and substitute the known values.

ΔT=ΔDD0α ΔT=0.6 cm100 cm×12×106 \degree C1 ΔT=0.61200×106 ΔT=0.61.2×103 ΔT=500 \degree C
💡 Teacher's Secret Hint

Pay attention to the powers of ten and unit cancellation. The 'cm' units cancel out, leaving the result in \degree C. A common mistake is to forget to convert units or to miscalculate the exponent in scientific notation.

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