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Physics Question 12 – NEET-UG 2025

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A 2 amp current is flowing through two different small circular copper coils having radii ratio 1:2. The ratio of their respective magnetic moments will be

The magnetic moment of a current loop is a measure of its strength as a magnetic source.

Video Walkthrough
Step 1: Recall the formula for magnetic moment✦ Active

The magnetic moment (M) of a circular current loop is given by the formula:

M=NIA

Where N is the number of turns, I is the current, and A is the area of the coil. For a circular coil, the area A=πr2, where r is the radius.

M=NI(πr2)
Step 2: Determine the proportionality of magnetic moment to radius○ Expand

The problem states that a 2 amp current is flowing through both coils, meaning the current I is the same for both. Assuming the number of turns N is also the same (as it's not specified to be different), and π is a constant, the magnetic moment M is directly proportional to the square of the radius r.

Mr2
💡 Teacher's Secret Hint

Always identify constant and variable parameters in ratio problems.

Step 3: Calculate the ratio of magnetic moments○ Expand

Given the radii ratio r1:r2=1:2. The ratio of their magnetic moments M1:M2 will be:

M1M2=r12r22=(r1r2)2

Substituting the given ratio:

M1M2=(12)2=14

Thus, the ratio of their respective magnetic moments is 1:4.

💡 Teacher's Secret Hint

Pay attention to whether the proportionality is linear, square, or inverse.

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