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Physics Question 41 – NEET-UG 2026

A car travels on a circular racetrack of radius 50 m, which is banked at an angle θ. If the car travels at a speed 10 ms1, then the wear and tear on its tyres is minimum. Taking the acceleration due to gravity to be 10 ms2, the value of θ is :

For a vehicle moving on a banked circular track, there is an optimum speed at which the vehicle can negotiate the curve without any reliance on friction, thus minimizing wear and tear on tyres.

Step 1: Recall the Formula for Banking Angle✦ Active

For a car traveling on a banked circular racetrack with minimum wear and tear on its tyres, it implies that no frictional force is required. The angle of banking θ for this condition is given by the formula:

tanθ=v2Rg

where v is the speed of the car, R is the radius of the track, and g is the acceleration due to gravity.

Step 2: Substitute Given Values○ Expand

Given values are: Radius R=50 m Speed v=10 ms1 Acceleration due to gravity g=10 ms2 Substitute these values into the formula:

tanθ=(10 ms1)2(50 m)(10 ms2)
💡 Teacher's Secret Hint

Ensure units are consistent before calculation.

Step 3: Calculate the Angle○ Expand

Perform the calculation:

tanθ=100500 tanθ=15

Therefore, the angle θ is:

θ=tan1(15)

This matches option (1).

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