Chemistry Q49 – NEET-UG 2026

In potash alum, the ratio of K

^{+}

and SO

_{4}^{2 -}

ions is

Recall the chemical formula for potash alum to determine its constituent ions.

Step 1: Recall the formula of Potash Alum✦ Active

Potash alum is a double salt with the chemical formula $KAl ({SO}_{4})_{2} \cdot 12 H_{2} O$ .

Step 2: Determine the ions formed upon dissociation○ Expand

When potash alum dissolves in water, it dissociates into its constituent ions:

KAl ({SO}_{4})_{2} \cdot 12 H_{2} O \to K^{+} + {Al}^{3 +} + 2 {SO}_{4}^{2 -} + 12 H_{2} O

From the dissociation, we can see there is 1 $K^{+}$ ion and 2 ${SO}_{4}^{2 -}$ ions.

💡 Teacher's Secret Hint

Remember that double salts dissociate completely into their individual ions in solution.

Step 3: Calculate the ratio○ Expand

The ratio of $K^{+}$ ions to ${SO}_{4}^{2 -}$ ions is $1 : 2$ .

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Chemistry Question 49 – NEET-UG 2026