Chemistry Question #75 – JEE-MAIN 2026

Name: Chemical Kinetics - JEE-MAIN 2026 Chemistry Q75 Walkthrough
Uploaded: 2026-07-04T12:00:00Z
Description: Step-by-step video solution walkthrough for Chemistry question from JEE-MAIN 2026 covering Chemical Kinetics.

Question

Decomposition of a hydrocarbon follows the equation k = (5.5 x 10^11 s^-1) e^(-28000K/T). The activation energy of reaction is _________ kJ mol^-1. (Nearest Integer) Given : R = 8.3 J K^-1 mol^-1

Accepted Answer

The correct answer is Option 232. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Chemistry Question 75 – JEE-MAIN 2026

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