Match List I with List II List I (Ion) List II (Group Number in Cation Analysis) Choose the correct answer from the options given below : A. Co2+ I. Group-I B. Mg2+ II. Group-III C. Pb2+ III. Group-IV D. Al3+ IV. Group-VI

The correct answer is Option 2. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Chemistry Q48 – NEET-UG 2025

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Match List I with List II Choose the correct answer from the options given below :

\begin{array}{lcl} List I (Ion) & List II (Group Number in Cation Analysis) \\ A. {Co}^{2 +} & I. Group-I \\ B. {Mg}^{2 +} & II. Group-III \\ C. {Pb}^{2 +} & III. Group-IV \\ D. {Al}^{3 +} & IV. Group-VI \end{array}

Clue 1 of 3: Qualitative Analysis Groups

Cation analysis involves separating and identifying different metal ions into groups based on their precipitation reactions with specific reagents.

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Step 1: Identify Cation Analysis Groups✦ Active

Qualitative inorganic analysis classifies cations into groups based on their precipitation reactions with specific group reagents. While the exact numbering can vary slightly between different schemes, a common classification is as follows:

- Group I: Precipitated as chlorides (e.g., $A g^{+}, P b^{2 +}, H g_{2}^{2 +}$ ) with dilute HCl.

- Group II: Precipitated as sulfides in acidic medium (e.g., $C u^{2 +}, C d^{2 +}$ ) with $H_{2} S$ in the presence of dilute HCl.

- Group III: Precipitated as hydroxides ( $F e^{3 +}, A l^{3 +}, C r^{3 +}$ ) with $N H_{4} O H$ in the presence of $N H_{4} C l$ . Some schemes extend this group to include sulfides ( $C o^{2 +}, N i^{2 +}, M n^{2 +}, Z n^{2 +}$ ) precipitated with $H_{2} S$ in ammoniacal medium, or separate these into a distinct Group IV.

- Group IV: Precipitated as carbonates (e.g., $B a^{2 +}, S r^{2 +}, C a^{2 +}$ ) with $(N H_{4})_{2} C O_{3}$ in the presence of $N H_{4} C l$ and $N H_{4} O H$ .

- Group V/VI: The soluble group, including $M g^{2 +}$ , $N a^{+}$ , $K^{+}$ , $N H_{4}^{+}$ , which do not precipitate with the reagents of the preceding groups.

Step 2: Match Ions to Their Respective Groups○ Expand

Based on the common qualitative analysis scheme, and considering the options provided, we can match the ions from List I to the Group Numbers in Cation Analysis from List II:

- A. $C o^{2 +}$ : While often considered Group III, some schemes classify $C o^{2 +}$ (along with $N i^{2 +}, M n^{2 +}, Z n^{2 +}$ ) into Group IV, where they precipitate as sulfides in ammoniacal medium. Thus, A matches with III (Group-IV).

- B. $M g^{2 +}$ : This ion belongs to the soluble group, which is often designated as Group V or Group VI, as it does not precipitate with the reagents of the preceding groups. Thus, B matches with IV (Group-VI).

- C. $P b^{2 +}$ : This ion precipitates as $P b C l_{2}$ with dilute HCl, placing it in Group I. Thus, C matches with I (Group-I).

- D. $A l^{3 +}$ : This ion precipitates as $A l (O H)_{3}$ with $N H_{4} O H$ in the presence of $N H_{4} C l$ , placing it in Group III. Thus, D matches with II (Group-III).

💡 Teacher's Secret Hint

Be aware that different qualitative analysis schemes might number or group certain cations slightly differently. Always check for consistency with the provided options.

Step 3: Select the Correct Option○ Expand

Combining the matches from Step 2, we get the following correspondence:

A - III

B - IV

C - I

D - II

Comparing this with the given options, option (2) is A-III, B-IV, C-I, D-II, which perfectly matches our derived mapping.

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Chemistry Question 48 – NEET-UG 2025

Clue 1 of 3: Qualitative Analysis Groups

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