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Chemistry Question 62 – JEE-MAIN 2026

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Match List - I with List - II. List - IList - IIChromium (III) ComplexesΔo(cm−1)(en = ethylene diamine)A. [Cr(CN)6]3−I. 15,060B. [CrF6]3−II. 17,400C. [Cr(H2O)6]3+III. 22,300D. [Cr(en)3]3+IV. 26,600 Choose the correct answer from the options given below :

The magnitude of crystal field splitting energy (Δo) depends on the nature of the ligand. Strong field ligands cause larger splitting, while weak field ligands cause smaller splitting.

● Video Walkthrough
Step 1: Determine Oxidation State and Ligand Field Strength✦ Active

All complexes are Chromium(III) complexes, meaning the central metal ion is Cr3+. The crystal field splitting energy (Δo) for octahedral complexes depends on the ligand field strength. We need to arrange the given ligands (CN−, F−, H2O, en) according to the spectrochemical series from weakest to strongest field:

F−<H2O<en<CN−
Step 2: Order Complexes by Increasing Δo○ Expand

Based on the ligand field strength, the complexes will have increasing Δo values in the following order:

[CrF6]3−<[Cr(H2O)6]3+<[Cr(en)3]3+<[Cr(CN)6]3−

The given Δo values in increasing order are: 15,060<17,400<22,300<26,600 cm−1.

💡 Teacher's Secret Hint

Remember that 'en' (ethylenediamine) is a bidentate ligand, but its position in the spectrochemical series is what matters for Δo.

Step 3: Match Complexes to Δo Values○ Expand

Matching the ordered complexes with the ordered Δo values:

B. [CrF6]3−→I. 15,060 cm−1C. [Cr(H2O)6]3+→II. 17,400 cm−1D. [Cr(en)3]3+→III. 22,300 cm−1A. [Cr(CN)6]3−→IV. 26,600 cm−1

This corresponds to the matching: A-IV, B-I, C-II, D-III. Comparing this with the given options, option 4 is the correct match.

💡 Teacher's Secret Hint

Double-check the order of ligands and corresponding Δo values to avoid common errors.

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