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Chemistry Question 62 – JEE-MAIN 2026

Match List - I with List - II. List - IList - IIChromium (III) ComplexesΔo(cm1)(en = ethylene diamine)A. [Cr(CN)6]3I. 15,060B. [CrF6]3II. 17,400C. [Cr(H2O)6]3+III. 22,300D. [Cr(en)3]3+IV. 26,600 Choose the correct answer from the options given below :

The magnitude of crystal field splitting energy (Δo) depends on the nature of the ligand. Strong field ligands cause larger splitting, while weak field ligands cause smaller splitting.

Step 1: Determine Oxidation State and Ligand Field Strength✦ Active

All complexes are Chromium(III) complexes, meaning the central metal ion is Cr3+. The crystal field splitting energy (Δo) for octahedral complexes depends on the ligand field strength. We need to arrange the given ligands (CN, F, H2O, en) according to the spectrochemical series from weakest to strongest field:

F<H2O<en<CN
Step 2: Order Complexes by Increasing Δo○ Expand

Based on the ligand field strength, the complexes will have increasing Δo values in the following order:

[CrF6]3<[Cr(H2O)6]3+<[Cr(en)3]3+<[Cr(CN)6]3

The given Δo values in increasing order are: 15,060<17,400<22,300<26,600 cm1.

💡 Teacher's Secret Hint

Remember that 'en' (ethylenediamine) is a bidentate ligand, but its position in the spectrochemical series is what matters for Δo.

Step 3: Match Complexes to Δo Values○ Expand

Matching the ordered complexes with the ordered Δo values:

B. [CrF6]3I. 15,060 cm1C. [Cr(H2O)6]3+II. 17,400 cm1D. [Cr(en)3]3+III. 22,300 cm1A. [Cr(CN)6]3IV. 26,600 cm1

This corresponds to the matching: A-IV, B-I, C-II, D-III. Comparing this with the given options, option 4 is the correct match.

💡 Teacher's Secret Hint

Double-check the order of ligands and corresponding Δo values to avoid common errors.

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