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Chemistry Question 62 – JEE-MAIN 2026

Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex? A. dxy=dyz>dz2 B. dxy=dyz>dz2 C. dx2y2>dz2>dxz D. dx2y2=dz2<dxz

Recall the splitting pattern of d-orbitals in a tetrahedral crystal field.

🥷
Ninja StrategyRecall Degeneracy

Knowing that dx2y2 and dz2 are degenerate in a tetrahedral field immediately eliminates any option that suggests they have different energies, such as option C.

Step 1: Understand d-orbital splitting in tetrahedral complexes✦ Active

In a tetrahedral crystal field, the five d-orbitals split into two sets: the lower energy e set and the higher energy t2 set. The e set comprises the dz2 and dx2y2 orbitals, which are degenerate. The t2 set comprises the dxy, dyz, and dxz orbitals, which are also degenerate. Therefore, the energy order is E(dxy)=E(dyz)=E(dxz)>E(dz2)=E(dx2y2). We can summarize this as t2>e.

Step 2: Evaluate each statement○ Expand

Let's evaluate each given statement based on the established energy order:

A. dxy=dyz>dz2: This statement is TRUE because dxy and dyz are both t2 orbitals (degenerate), and t2 orbitals are higher in energy than dz2 (an e orbital).

B. dxy=dyz>dz2: This statement is identical to A, and thus is also TRUE.

C. dx2y2>dz2>dxz: This statement is FALSE. dx2y2 and dz2 are degenerate (e orbitals), so dx2y2=dz2. Also, dz2 (an e orbital) is lower in energy than dxz (a t2 orbital), so dz2<dxz.

D. dx2y2=dz2<dxz: This statement is TRUE. dx2y2 and dz2 are degenerate (e orbitals), and e orbitals are lower in energy than dxz (a t2 orbital).

💡 Teacher's Secret Hint

Pay close attention to the degeneracy within the e and t2 sets, and the relative energy order between the sets.

Step 3: Identify the correct combination○ Expand

From the evaluation, statements A, B, and D are true. Therefore, the option that includes A, B, and D is the correct answer.

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