Chemistry Question #74 – JEE-MAIN 2026

Name: Chemical Kinetics - JEE-MAIN 2026 Chemistry Q74 Walkthrough
Uploaded: 2026-07-04T12:00:00Z
Description: Step-by-step video solution walkthrough for Chemistry question from JEE-MAIN 2026 covering Chemical Kinetics.

Question

For reaction A -> P, rate constant k = 1.5 x 10^3 s^-1 at 27°C If activation energy for the above reaction is 60 kJ mol^-1, then the temperature (in °C) at which rate constant, k = 4.5 x 10^3 s^-1 is _______. (Nearest integer) Given : log 2 = 0.30, log 3 = 0.48, R = 8.3 J K^-1 mol^-1, ln 10 = 2.3

Accepted Answer

The correct answer is Option 41. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Chemistry Question 74 – JEE-MAIN 2026

Ready to master this concept? 🚀