Physics Question 31 – JEE-MAIN 2026
A metal string is suspended from a rigid support and its free end is attached to a block of mass . Second block having mass is suspended at the bottom of the first block using a string . The area of cross sections of strings and are same. The ratio of lengths of strings to is and the ratio of their Young's moduli ( ) is . The ratio of elongations in to is _______.
🧠 Full Solution Path
Step 1: Determine the forces on each string✦ Active
String A supports both blocks, so the total force on string A is
String B supports only the lower block, so the force on string B is
Step 2: Recall the formula for elongation○ Expand
The elongation
Step 3: Calculate the ratio of elongations○ Expand
For string A,
Given
Thus, the ratio of elongations in A to B is 6.
💡 Teacher's Secret Hint
Ensure correct identification of forces for each string and careful substitution of ratios.
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