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Chemistry Question 52 – JEE-MAIN 2026

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Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. A. n=3,l=2,m=+1 B. n=4,l=0,m=0 C. n=6,l=1,m=0 D. n=5,l=1,m=+1 E. n=2,l=1,m=+1 Choose the correct answer from the options given below:

For multi-electron atoms, the energy of an atomic orbital depends on both the principal quantum number (n) and the azimuthal quantum number (l).

Step 1: Apply the (n+l) rule for multi-electron atoms✦ Active

For multi-electron atoms, the energy of an orbital is determined by the (n+l) rule. Orbitals with a lower (n+l) value have lower energy. If two orbitals have the same (n+l) value, the orbital with the lower principal quantum number (n) has lower energy. The magnetic quantum number (m) does not affect the energy.

Step 2: Calculate (n+l) for each orbital○ Expand

We calculate the sum of the principal quantum number (n) and the azimuthal quantum number (l) for each given orbital:

A. n=3,l=2⟹(n+l)=3+2=5 B. n=4,l=0⟹(n+l)=4+0=4 C. n=6,l=1⟹(n+l)=6+1=7 D. n=5,l=1⟹(n+l)=5+1=6 E. n=2,l=1⟹(n+l)=2+1=3
Step 3: Arrange orbitals in increasing order of energy○ Expand

Based on the calculated (n+l) values, the order of increasing energy is:

E(n+l=3)<B(n+l=4)<A(n+l=5)<D(n+l=6)<C(n+l=7)

This corresponds to the sequence E<B<A<D<C. Comparing this with the given options, option 4 is the correct answer.

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