Chemistry Q52 – JEE-MAIN 2025

Home Chemistry Structure of AtomQuestion #621

For electrons in

2 s

and

2 p

orbitals, the orbital angular momentum values, respectively are :

Clue 1 of 3: Orbital Angular Momentum

The orbital angular momentum of an electron is quantized and depends on its azimuthal quantum number ( $l$ ).

🥷

Ninja Strategy•Quantum Number Recall & Elimination

Quickly recall that for an s-orbital, l=0, which means its angular momentum is 0. This eliminates options that don't start with 0. Then, calculate for the p-orbital (l=1) to distinguish between the remaining options.

🧠 Full Solution Path

Step 1: Identify Azimuthal Quantum Numbers✦ Active

For an electron in a $2 s$ orbital, the azimuthal quantum number is $l = 0$ . For an electron in a $2 p$ orbital, the azimuthal quantum number is $l = 1$ .

Step 2: Calculate Orbital Angular Momentum for 2s orbital○ Expand

Using the formula for orbital angular momentum, $L = \sqrt{l (l + 1)} \frac{h}{2 π}$ :

L_{2 s} = \sqrt{0 (0 + 1)} \frac{h}{2 π} = \sqrt{0} \frac{h}{2 π} = 0

💡 Teacher's Secret Hint

Remember that for s-orbitals, the angular momentum is always zero.

Step 3: Calculate Orbital Angular Momentum for 2p orbital○ Expand

Using the formula for orbital angular momentum for the $2 p$ orbital ( $l = 1$ ):

L_{2 p} = \sqrt{1 (1 + 1)} \frac{h}{2 π} = \sqrt{2} \frac{h}{2 π}

Thus, the orbital angular momentum values for $2 s$ and $2 p$ orbitals are $0$ and $\sqrt{2} \frac{h}{2 π}$ , respectively.

💡 Teacher's Secret Hint

Ensure you correctly substitute the value of $l$ for the p-orbital.

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Chemistry Question 52 – JEE-MAIN 2025

Clue 1 of 3: Orbital Angular Momentum

🧠 Full Solution Path