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Maths Question 13 – JEE-MAIN 2026

If the point of intersection of the lines x+13=y+a5=z+b+17 and x21=yb4=z2a7 lies on xy-plane, then the value of a+b is:

Represent the coordinates of a general point on each line using a parameter.

Step 1: Represent points on lines and apply z=0 condition✦ Active

Let the first line be equal to λ and the second line be equal to μ. The general point on the first line is P1(3λ1,5λa,7λb1). The general point on the second line is P2(μ+2,4μ+b,7μ+2a). Since the point of intersection lies on the xy-plane, its z-coordinate must be 0.

7λb1=0b=7λ1(1) 7μ+2a=0a=72μ(2)
Step 2: Equate coordinates and solve for parameters○ Expand

For the lines to intersect, the coordinates of P1 and P2 must be equal. Equating the x and y coordinates:

3λ1=μ+23λμ=3(3) 5λa=4μ+b(4)

Substitute equations (1) and (2) into equation (4):

5λ(72μ)=4μ+(7λ1) 10λ+7μ=8μ+14λ2 4λμ=24λ+μ=2(5)

Now, solve the system of equations (3) and (5):

(3λμ)+(4λ+μ)=3+27λ=5λ=57 3(57)μ=3157μ=3μ=1573=67
💡 Teacher's Secret Hint

Ensure careful algebraic manipulation when substituting and solving the system of equations.

Step 3: Calculate a, b, and a+b○ Expand

Substitute the values of λ and μ back into equations (1) and (2) to find a and b:

b=7λ1=7(57)1=51=4 a=72μ=72(67)=3

Finally, calculate a+b:

a+b=3+4=7
💡 Teacher's Secret Hint

Double-check the calculations for a and b to avoid arithmetic errors.

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