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Chemistry Question 62 – JEE-MAIN 2026

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Given below are two statements : Statement I: A mixture of C12H22O11 (sugar) and NaCl can be separated by dissolving sugar in alcohol, due to differential solubility. Statement II: Rose essence from rose petals is seperated by steam distillation due to its high volatility and insolubility in H2O. In the light of the above statements, choose the correct answer from the options given below :

Consider the principles behind common separation methods like differential solubility and distillation.

Step 1: Evaluate Statement I (Differential Solubility)✦ Active

Statement I claims that a mixture of sugar (C12H22O11) and NaCl can be separated by dissolving sugar in alcohol due to differential solubility. Sugar is sparingly soluble in alcohol (e.g., ethanol), while NaCl is largely insoluble in alcohol. This difference in solubility allows for the separation of the two components, as sugar would dissolve to some extent, leaving NaCl undissolved. Therefore, Statement I is true.

Step 2: Evaluate Statement II (Steam Distillation)○ Expand

Statement II states that rose essence from rose petals is separated by steam distillation due to its high volatility and insolubility in H2O. Rose essence (rose oil) consists of volatile organic compounds that are largely immiscible with water. Steam distillation is a suitable technique for separating such volatile, water-immiscible substances from non-volatile plant materials. The principle relies on the combined vapor pressures of water and the organic compound, allowing distillation at a lower temperature than the boiling point of either pure component, thus preventing decomposition. Therefore, Statement II is true.

Step 3: Conclusion○ Expand

Since both Statement I and Statement II are true, the correct option is 'Both Statement I and Statement II are true'.

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