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Physics Question 41 – JEE-MAIN 2026

The energy released if hydrogen atoms are combined to form 24He is _______ MeV. (Take binding energies per nucleon of 12H and 24He as 1.1 MeV and 7.2 MeV, respectively)

Energy is released when lighter nuclei combine to form a heavier, more stable nucleus. This energy release is related to the change in binding energy.

Step 1: Identify the Nuclear Reaction and Calculate Total Binding Energies of Reactants✦ Active

The fusion reaction to form 24He from hydrogen atoms (specifically deuterium, 12H, as its binding energy is provided) is:

2 12H 24He

The binding energy per nucleon for 12H is 1.1 MeV. Therefore, the total binding energy of one 12H nucleus is 2×1.1 MeV=2.2 MeV. The total binding energy of the reactants (2 12H) is 2×2.2 MeV=4.4 MeV.

Step 2: Calculate Total Binding Energy of the Product○ Expand

The binding energy per nucleon for 24He is 7.2 MeV. The total binding energy of one 24He nucleus is 4×7.2 MeV=28.8 MeV.

Step 3: Calculate the Energy Released○ Expand

The energy released (Q-value) in a nuclear reaction is the difference between the total binding energy of the products and the total binding energy of the reactants:

Energy released=BE(products)BE(reactants)

Substituting the calculated values:

Energy released=BE(24He)2×BE(12H) Energy released=28.8 MeV4.4 MeV=24.4 MeV
💡 Teacher's Secret Hint

Ensure you subtract the total binding energy of all reactant nuclei from the total binding energy of all product nuclei.

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