Physics Q83 – AP-EAMCET 2026

Home Physics Motion in a PlaneQuestion #301

If the vertical displacement of a body projected at an angle with the horizontal during the first second of its motion is

15 m

, then the maximum height reached by it is (acceleration due to gravity

= 10 {ms}^{- 2}

)

Clue 1 of 3: Projectile Motion

Understand that the vertical motion of a projectile is governed by constant acceleration due to gravity, independent of its horizontal motion.

🧠 Full Solution Path

Step 1: Identify given parameters and relevant equations for vertical motion✦ Active

The problem provides the vertical displacement during the first second ( $S_{y} = 15 m$ ), the time ( $t = 1 s$ ), and the acceleration due to gravity ( $g = 10 {ms}^{- 2}$ ). We need to find the maximum height ( $H_{m a x}$ ). For vertical motion under gravity, the relevant kinematic equation is $S_{y} = u_{y} t + \frac{1}{2} a_{y} t^{2}$ . Since gravity acts downwards, $a_{y} = - g$ . The formula for maximum height is $H_{m a x} = \frac{u_{y}^{2}}{2 g}$ , where $u_{y}$ is the initial vertical velocity.

Step 2: Calculate the initial vertical velocity (

u_{y}

)○ Expand

Substitute the given values into the vertical displacement equation:

S_{y} = u_{y} t - \frac{1}{2} g t^{2}

15 = u_{y} (1) - \frac{1}{2} (10) (1)^{2}

15 = u_{y} - 5

u_{y} = 15 + 5

u_{y} = 20 m/s

💡 Teacher's Secret Hint

Remember to use the correct sign for acceleration due to gravity. Since the body is moving upwards initially, and gravity acts downwards, we use $- g$ .

Step 3: Calculate the maximum height (

H_{m a x}

)○ Expand

Now that we have the initial vertical velocity $u_{y} = 20 m/s$ , we can use the maximum height formula:

H_{m a x} = \frac{u_{y}^{2}}{2 g}

H_{m a x} = \frac{(20)^{2}}{2 \times 10}

H_{m a x} = \frac{400}{20}

H_{m a x} = 20 m

💡 Teacher's Secret Hint

The maximum height is reached when the vertical component of velocity becomes zero. This formula is derived from $v_{y}^{2} = u_{y}^{2} + 2 a_{y} S_{y}$ by setting $v_{y} = 0$ and $S_{y} = H_{m a x}$ .

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Physics Question 83 – AP-EAMCET 2026

Clue 1 of 3: Projectile Motion

🧠 Full Solution Path