For the following reaction sequence, choose the correct option Benzene reacts with i. CH3COCl, AlCl3 then ii. NaOCl to give P + Q

The correct answer is Option 3. Full mathematical solution steps and hints are accessible in the interactive StemCET workspace.

Chemistry Q46 – NEET-UG 2026

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Home Chemistry Organic Chemistry – Some Basic Principles and TechniquesQuestion #475

For the following reaction sequence, choose the correct option

Benzene \overset{i. {CH}_{3} COCl, {AlCl}_{3} ii. NaOCl}{\to} P + Q

Clue 1 of 3: Reaction Sequence Identification

The reaction sequence involves two distinct named reactions: Friedel-Crafts acylation followed by the haloform reaction.

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Ninja Strategy•Product Identification and Functional Group Analysis

Correctly identifying the products P (sodium benzoate) and Q (chloroform) from the reaction sequence allows for quick elimination of options based on their functional groups and aromaticity.

🧠 Full Solution Path

Step 1: Identify the Reaction Sequence and Intermediate Product✦ Active

The first step is Friedel-Crafts acylation of benzene with acetyl chloride ( $C H_{3} C O C l$ ) in the presence of anhydrous $A l C l_{3}$ . This yields acetophenone ( $C_{6} H_{5} C O C H_{3}$ ). $C_{6} H_{6} + C H_{3} C O C l \overset{A l C l_{3}}{\to} C_{6} H_{5} C O C H_{3} + H C l$

Step 2: Determine the Final Products P and Q from the Haloform Reaction○ Expand

The second step is the reaction of acetophenone ( $C_{6} H_{5} C O C H_{3}$ ) with sodium hypochlorite ( $N a O C l$ ), which is a haloform reaction. Acetophenone, being a methyl ketone, undergoes this reaction to form sodium benzoate ( $C_{6} H_{5} C O O N a$ ) and chloroform ( $C H C l_{3}$ ). $C_{6} H_{5} C O C H_{3} + 3 N a O C l \to C_{6} H_{5} C O O N a + C H C l_{3} + 2 N a O H$ So, $P$ and $Q$ are sodium benzoate ( $C_{6} H_{5} C O O N a$ ) and chloroform ( $C H C l_{3}$ ).

💡 Teacher's Secret Hint

Remember that the haloform reaction converts the methyl ketone group into a carboxylate and a haloform.

Step 3: Evaluate Each Option Based on Products P and Q○ Expand

Let's assume $P$ is sodium benzoate ( $C_{6} H_{5} C O O N a$ ) and $Q$ is chloroform ( $C H C l_{3}$ ). (1) $P$ is the sodium salt of a carboxylic acid (correct), but $Q$ (chloroform) is not a primary alcohol (incorrect). (2) $P$ (sodium benzoate) is aromatic (correct), but $Q$ (chloroform) is not aromatic (incorrect). (3) $P$ (sodium benzoate) on acidification gives benzoic acid (a carboxylic acid, correct). $Q$ (chloroform) on exposure to air and light oxidizes to phosgene ( $C O C l_{2}$ ), which is a poisonous gas (correct). (4) $P$ (sodium benzoate) is a carbonyl compound (correct), but $Q$ (chloroform) is not a carbonyl compound (incorrect). Therefore, option (3) is the correct statement.

💡 Teacher's Secret Hint

Recall the properties and reactions of chloroform, especially its decomposition in the presence of light and air.

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Chemistry Question 46 – NEET-UG 2026

Clue 1 of 3: Reaction Sequence Identification

🧠 Full Solution Path