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Physics Question 43 – JEE-MAIN 2026

A circular current loop of radius R is placed inside square loop of side length L (L>>R) such that they are co-planar and their centers coincide. The permeability of free space is μ0. The mutual inductance between circular loop and square loop is _______.

Mutual inductance M between two coils is defined by the relation Φ=MI, where Φ is the magnetic flux through one coil due to current I in the other.

Step 1: Calculate Magnetic Field at the Center of the Square Loop✦ Active

The magnetic field at the center of a square loop of side L carrying current Is is the sum of the fields due to its four sides. For one side, the magnetic field at the center is given by Bside=μ0Is4π(L/2)(sin45+sin45). Summing for all four sides, the total magnetic field at the center is:

Bcenter=4×μ0Is2πL(2×12)=22μ0IsπL
Step 2: Calculate Magnetic Flux through the Circular Loop○ Expand

Since the circular loop of radius R is much smaller than the square loop (L>>R) and concentric, the magnetic field Bcenter can be considered uniform over its area. The area of the circular loop is Ac=πR2. The magnetic flux Φc through the circular loop due to the current Is in the square loop is:

Φc=BcenterAc=(22μ0IsπL)(πR2)=22μ0IsR2L
Step 3: Determine Mutual Inductance○ Expand

By the definition of mutual inductance, Φc=MIs. Equating the two expressions for flux, we get:

MIs=22μ0IsR2L

Therefore, the mutual inductance M is:

M=22μ0R2L
💡 Teacher's Secret Hint

Ensure to use the correct approximation for the magnetic field when one loop is much smaller than the other and concentric.

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