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Chemistry Question 62 – JEE-MAIN 2025

An octahedral complex having molecular composition Co.5NH3.Cl.SO4 has two isomers A and B. The solution of A gives a white precipitate with AgNO3 solution and the solution of B gives white precipitate with BaCl2 solution. The type of isomerism exhibited by the complex is,

The formation of precipitates with AgNO3 and BaCl2 indicates the presence of specific free ions in solution.

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Ninja StrategyReactivity of Counter Ions

The differential reactivity of isomers A and B with AgNO3 and BaCl2 directly indicates that different ions are acting as counter ions, which is the defining characteristic of ionisation isomerism.

Step 1: Determine the structure of Isomer A✦ Active

Isomer A gives a white precipitate with AgNO3 solution, indicating the presence of free Cl ions in the solution. Therefore, Cl must be outside the coordination sphere. Given the molecular formula Co.5NH3.Cl.SO4 and an octahedral complex (coordination number 6), the structure of Isomer A is [Co(NH3)5SO4]Cl. The oxidation state of Co is +3 (x+5(0)+(2)=+1x=+3).

Step 2: Determine the structure of Isomer B○ Expand

Isomer B gives a white precipitate with BaCl2 solution, indicating the presence of free SO42 ions in the solution. Therefore, SO42 must be outside the coordination sphere. The structure of Isomer B is [Co(NH3)5Cl]SO4. The oxidation state of Co is +3 (x+5(0)+(1)=+2x=+3).

Step 3: Identify the type of isomerism○ Expand

Isomer A is [Co(NH3)5SO4]Cl and Isomer B is [Co(NH3)5Cl]SO4. These two isomers have the same molecular formula but differ in the ions that are inside the coordination sphere and those that are outside as counter ions. Specifically, Cl and SO42 exchange positions between the coordination sphere and the ionization sphere. This phenomenon is known as ionisation isomerism.

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