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Physics Question 13 – NEET-UG 2023

The magnetic energy stored in an inductor of inductance 4μH carrying a current of 2 A is :

Inductors store energy in their magnetic fields when a current flows through them.

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Ninja StrategyFormula Application and Unit Awareness

Correctly apply the energy formula U=12LI2 and pay close attention to the micro- (106) prefix in the inductance and the expected energy unit.

Step 1: Identify the Formula for Energy in an Inductor✦ Active

The magnetic energy (U) stored in an inductor with inductance L carrying a current I is given by the formula:

U=12LI2
Step 2: Convert Units and Substitute Values○ Expand

Given inductance L=4μH. Convert it to Henrys: L=4×106 H. Given current I=2 A. Substitute these values into the formula:

U=12×(4×106 H)×(2 A)2
💡 Teacher's Secret Hint

Remember to convert microhenrys to henrys before calculation.

Step 3: Calculate the Energy○ Expand

Perform the calculation:

U=12×4×106×4 U=8×106 J U=8μJ

This matches option (4).

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