Chemistry Q65 – JEE-MAIN 2026

Home Chemistry Organic Chemistry – Some Basic Principles and TechniquesQuestion #473

Correct statements regarding alkyl halides (R-X) among the following are: A. Alcohol being less polar solvent as compared to water, alcoholic KOH favours elimination reaction with R-X. B. Order of reactivity towards

S_{N} 1

mechanism is

C_{6} H_{5} - C H_{2} - C l > C_{6} H_{5} - C H C l - C_{6} H_{5}

. C. Non substituted aryl halides exhibit properties similar to alkyl halides. D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne. E.

R - C l

can be prepared by reacting

R - O H

with

S O C l_{2}

but

A r - C l

cannot be prepared by reacting

A r - O H

with

S O C l_{2}

. Choose the correct answer from the options given below :

Clue 1 of 3: Reaction Conditions and Mechanisms

Consider how solvent polarity affects reaction pathways (elimination vs. substitution) and the factors influencing carbocation stability in $S_{N} 1$ reactions.

🥷

Ninja Strategy•Statement-by-Statement Elimination

Evaluate each statement individually for correctness. Once an incorrect statement is identified, eliminate all options that contain that incorrect statement. This quickly narrows down to the correct choice.

🧠 Full Solution Path

Step 1: Evaluate Statements A, B, and C✦ Active

Statement A: Alcoholic KOH is a strong base and in a less polar solvent (alcohol compared to water), it favors elimination (E2) over substitution (SN2) for alkyl halides. This statement is correct.

Statement B: $S_{N} 1$ reactivity depends on carbocation stability. The carbocation from $C_{6} H_{5} - C H C l - C_{6} H_{5}$ ( $C_{6} H_{5} - C H^{+} - C_{6} H_{5}$ ) is stabilized by resonance with two phenyl groups, making it more stable than the carbocation from $C_{6} H_{5} - C H_{2} - C l$ ( $C_{6} H_{5} - C H_{2}^{+}$ ) which has only one phenyl group. Thus, $C_{6} H_{5} - C H C l - C_{6} H_{5}$ is more reactive towards $S_{N} 1$ . The statement is incorrect.

Statement C: Aryl halides (halogen directly on aromatic ring) have partial double bond character in the C-X bond due to resonance and the $s p^{2}$ hybridized carbon, making them significantly less reactive towards nucleophilic substitution compared to alkyl halides. Their properties are not similar. This statement is incorrect.

💡 Teacher's Secret Hint

Remember that alcoholic KOH is a strong base, while aqueous KOH is a strong nucleophile. For $S_{N} 1$ reactions, always compare the stability of the intermediate carbocations.

Step 2: Evaluate Statements D and E○ Expand

Statement D: Vinyl chloride ( $C H_{2} = C H - C l$ ) is a haloalkene (halogen on $s p^{2}$ carbon). Allyl chloride ( $C H_{2} = C H - C H_{2} - C l$ ) is an allylic halide, where the halogen is on an $s p^{3}$ carbon adjacent to a double bond. It is a type of haloalkene, not a haloalkyne. This statement is incorrect.

Statement E: Alcohols ( $R - O H$ ) react with thionyl chloride ( $S O C l_{2}$ ) to form alkyl chlorides ( $R - C l$ ) efficiently (Darzen's process). However, phenols ( $A r - O H$ ) do not react with $S O C l_{2}$ to form aryl chlorides ( $A r - C l$ ) due to the partial double bond character of the C-O bond in phenols and the stability of the aromatic ring. This statement is correct.

💡 Teacher's Secret Hint

Distinguish between vinyl, allyl, and aryl halides based on the position of the halogen relative to double bonds or aromatic rings. Recall the specific limitations of reagents like $S O C l_{2}$ for different classes of organic compounds.

Step 3: Identify Correct Option○ Expand

From the evaluation, statements A and E are correct. Therefore, the option that includes both A and E is the correct answer.

💡 Teacher's Secret Hint

Once you've identified all correct individual statements, match them to the given options.

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Chemistry Question 65 – JEE-MAIN 2026

Clue 1 of 3: Reaction Conditions and Mechanisms

🧠 Full Solution Path