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Physics Question 10 – NEET-UG 2023

Light travels a distance x in time t1 in air and 10x in time t2 in another denser medium. What is the critical angle for this medium?

Recall that the speed of light changes in different media, and this change is quantified by the refractive index.

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Ninja StrategyPhysical Constraints on Critical Angle

The argument of sin1 for a critical angle must be between 0 and 1. By establishing the relationship t2>10t1 (from vair>vmedium for a denser medium), options (1) and (2) can be immediately eliminated as their arguments become greater than 1.

Step 1: Calculate Speeds of Light✦ Active

The speed of light in air (vair) and in the denser medium (vmedium) can be calculated using the formula speed = distance/time.

vair=xt1 vmedium=10xt2
Step 2: Determine Refractive Index of Denser Medium○ Expand

The refractive index of the denser medium (nmedium) with respect to air is the ratio of the speed of light in air to the speed of light in the medium. We assume the refractive index of air is approximately 1.

nmedium=vairvmedium=x/t110x/t2=xt1×t210x=t210t1
💡 Teacher's Secret Hint

Remember that for a denser medium, nmedium must be greater than 1, which implies t2>10t1 from our calculation.

Step 3: Calculate Critical Angle○ Expand

The critical angle (θc) for light traveling from the denser medium to air is given by sinθc=1nmedium (since nair1). Substitute the value of nmedium.

sinθc=1t210t1=10t1t2 θc=sin1(10t1t2)
💡 Teacher's Secret Hint

The argument of sin1 must be between 0 and 1 for a real angle. This means 10t1t21.

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