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Physics Question 34 – JEE-MAIN 2025

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Match List - I with List - II. List - IList - II(A) Isothermal(I) ΔW (work done) =0(B) Adiabatic(II) ΔQ (supplied heat) =0(C) Isobaric(III) ΔU (change in internal energy) ≠0(D) Isochoric(IV) ΔU=0 Choose the correct answer from the options given below :

Recall the definitions and characteristics of isothermal, adiabatic, isobaric, and isochoric processes.

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Ninja Strategy•Sequential Elimination

Start by identifying the most definitive matches (Isothermal and Adiabatic) and eliminate options that contradict these, narrowing down to the correct answer.

Step 1: Define each thermodynamic process and its implications✦ Active

Let's analyze each process from List-I and identify the corresponding condition from List-II based on the definitions and the First Law of Thermodynamics (ΔU=ΔQ−ΔW).

(A) Isothermal Process:Temperature T is constant. For an ideal gas, internal energy U depends only on T, so ΔU=0.(B) Adiabatic Process:No heat exchange with surroundings, so ΔQ=0.(C) Isobaric Process:Pressure P is constant. Generally, ΔU≠0,ΔQ≠0,ΔW≠0.(D) Isochoric Process:Volume V is constant. Since ΔV=0, work done ΔW=PΔV=0.
Step 2: Match List-I with List-II○ Expand

Based on the definitions from Step 1, we can establish the following matches:

(A) Isothermal→(IV) ΔU=0(B) Adiabatic→(II) ΔQ=0(C) Isobaric→(III) ΔU≠0 (This is the general case, as ΔU is not necessarily zero for an isobaric process unless it's also isothermal)(D) Isochoric→(I) ΔW=0
💡 Teacher's Secret Hint

Remember that for an ideal gas, internal energy is a function of temperature only. Also, work done is zero if volume is constant.

Step 3: Select the correct option○ Expand

The correct matching is (A)-(IV), (B)-(II), (C)-(III), (D)-(I). Comparing this with the given options, Option 4 matches this sequence.

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