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Biology Question 120 – NEET-UG 2024

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Formation of interfascicular cambium from fully developed parenchyma cells is an example for

Plant cells exhibit plasticity, meaning they can change their developmental pathway under certain conditions.

Step 1: Understand Cell Differentiation Processes✦ Active

Differentiation is the process by which cells become specialized in structure and function. Dedifferentiation is the process where already differentiated cells lose their specialization and regain the capacity to divide. Redifferentiation is when dedifferentiated cells again differentiate to form new specialized cells.

Step 2: Analyze Interfascicular Cambium Formation○ Expand

Interfascicular cambium is formed from the parenchyma cells of the medullary rays. These parenchyma cells are fully developed and differentiated cells. For them to form cambium (a meristematic tissue capable of division), they must first lose their differentiated state and regain the ability to divide.

💡 Teacher's Secret Hint

The key is that parenchyma cells are already 'fully developed' or differentiated.

Step 3: Conclude the Process○ Expand

Since fully developed (differentiated) parenchyma cells revert to a meristematic (undifferentiated, dividing) state to form interfascicular cambium, this process is an example of dedifferentiation.

💡 Teacher's Secret Hint

This is a classic example of dedifferentiation in secondary growth of plants.

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