Chemistry Question 55 – JEE-MAIN 2026
19.5 g of fluoro acetic acid (molar mass = 78 g mol ) is dissolved in 500 g of water at 298 K. The depression in the freezing point of water was 1°C. What is of fluoro acetic acid ? (For water, =1.86 K kg mol ). Assume molarity and molality to have same values.
🧠 Full Solution Path
Step 1: Calculate Molality and Van't Hoff Factor✦ Active
First, calculate the moles of fluoro acetic acid and the molality of the solution. Then, use the freezing point depression formula to find the Van't Hoff factor (
Step 2: Determine the Degree of Dissociation ( )○ Expand
For a weak acid (HFA) that dissociates into two ions (H
Step 3: Calculate the Acid Dissociation Constant ( )○ Expand
The acid dissociation constant (
Rounding this value,
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Ensure to use the correct formula for
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