Chemistry Q55 – NEET-UG 2023

Home Chemistry ElectrochemistryQuestion #396

The conductivity of centimolar solution of KCl at

25^{\circ} C

0.0210 {ohm}^{- 1} {cm}^{- 1}

and the resistance of the cell containing the solution at

25^{\circ} C

60 ohm

. The value of cell constant is -

Clue 1 of 3: Electrochemistry Fundamentals

The cell constant is a characteristic property of a conductivity cell, relating its dimensions to the measured resistance and conductivity.

🧠 Full Solution Path

Step 1: Identify the Relationship between Conductivity, Resistance, and Cell Constant✦ Active

The cell constant ( $G^{*}$ ) of a conductivity cell is related to the conductivity ( $κ$ ) of the solution and the measured resistance ( $R$ ) by the formula:

κ = \frac{1}{R} \times G^{*}

Rearranging this, we get the formula for the cell constant:

G^{*} = κ \times R

Step 2: Substitute the Given Values○ Expand

Given conductivity ( $κ$ ) = $0.0210 {ohm}^{- 1} {cm}^{- 1}$

Given resistance ( $R$ ) = $60 ohm$

Substitute these values into the formula:

G^{*} = (0.0210 {ohm}^{- 1} {cm}^{- 1}) \times (60 ohm)

💡 Teacher's Secret Hint

Ensure units are consistent before calculation. Here, ohm and ohm $^{- 1}$ cancel out, leaving cm $^{- 1}$ .

Step 3: Calculate the Cell Constant○ Expand

Perform the multiplication:

G^{*} = 1.26 {cm}^{- 1}

Comparing this value with the given options, option (3) is $1.26 {cm}^{- 1}$ .

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Chemistry Question 55 – NEET-UG 2023

Clue 1 of 3: Electrochemistry Fundamentals

🧠 Full Solution Path