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Maths Question 9 – JEE-MAIN 2025

The mean and standard deviation of 100 observations are 40 and 5.1, respectively. By mistake one observation is taken as 50 instead of 40. If the correct mean and the correct standard deviation are μ and σ respectively, then 10(μ+σ) is equal to

When an observation is corrected, both the sum of observations and the sum of squares of observations need to be adjusted.

Step 1: Calculate Corrected Sum and Mean✦ Active

First, use the given incorrect mean to find the incorrect sum of observations. Then, adjust this sum by subtracting the incorrect observation and adding the correct one to find the correct sum. Finally, calculate the correct mean μ.

xinc=n×x¯inc=100×40=4000 xcorr=xinc50+40=400010=3990 μ=xcorrn=3990100=39.9
Step 2: Calculate Corrected Sum of Squares and Standard Deviation○ Expand

Next, use the incorrect standard deviation and mean to find the incorrect sum of squares. Adjust this sum of squares by subtracting the square of the incorrect observation and adding the square of the correct one. Use the corrected sum of squares and the correct mean to find the correct standard deviation σ.

σinc2=xinc2n(x¯inc)2 5.12=xinc2100402 26.01=xinc21001600 xinc2=100(1600+26.01)=162601 xcorr2=xinc2502+402=1626012500+1600=161701 σ2=xcorr2nμ2=161701100(39.9)2=1617.011592.01=25 σ=25=5
Step 3: Calculate the Final Expression○ Expand

Finally, substitute the calculated values of μ and σ into the expression 10(μ+σ).

10(μ+σ)=10(39.9+5)=10(44.9)=449
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