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Physics Question 39 – JEE-MAIN 2025

The unit of 2Iϵ0c is : (I= intensity of an electromagnetic wave, c: speed of light)

Consider the fundamental relationship between the intensity of an electromagnetic wave and its electric field strength.

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Ninja StrategyRecognize the Electric Field

The given expression directly corresponds to the electric field strength of an electromagnetic wave, whose standard unit is N/C or V/m.

Step 1: Identify the Physical Quantity✦ Active

The intensity I of an electromagnetic wave is related to its peak electric field strength E0 by the formula:

I=12ϵ0cE02

Rearranging this formula to solve for E0, we get:

E02=2Iϵ0cE0=2Iϵ0c

Thus, the expression given in the question represents the peak electric field strength (E0) of an electromagnetic wave.

Step 2: Determine the Unit of Electric Field○ Expand

The standard unit for electric field strength (E) is Volt per meter (V/m) or Newton per Coulomb (N/C). These two units are equivalent.

To show equivalence: V=J/C and J=Nm. So, V/m=(J/C)/m=(Nm)/(Cm)=N/C.

Step 3: Match with Options○ Expand

Now, we compare the unit of electric field (N/C) with the given options:

1. Vm (Volt-meter): This is a unit of electric potential multiplied by distance.

2. NC1 (Newton per Coulomb): This is equivalent to N/C, which is a unit of electric field.

3. NC (Newton-Coulomb): This is a unit of force multiplied by charge.

4. Nm (Newton-meter): This is a unit of work or energy (Joule).

Therefore, the correct option is NC1.

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